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Post by Ark on Mar 5, 2006 14:00:31 GMT -5
It's finally here, Tricky Trivia brought to you by ark.
Here's the plan, one question a week. Whoever gets it right gets one credit. Get three, and i give you a prize, also, for math questions you must explain your process.
Question one.
THe three primary colors are each given a different value. Starting in alphabetical order, the values are 1,2, and 3. Calculate the values of these colors. Red, Blue, Yellow, Green, Purple, Orange, Red orange, Yellow Orange, Indigo, Magenta, Bluegreen, Yellow Green, White, and black. Give the individual values as well as the total of all oof them, as well as the product of all of them.
(Hint: Beauty over brains.)
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Post by wirrawong on Mar 5, 2006 19:37:48 GMT -5
Blue= 1
Red= 2
Yellow= 3
Green= Blue + Yellow= 1 + 3= 4
Purple= Blue + Red= 1 + 2= 3
Orange= Red + Yellow= 2 + 3= 5
Red Orange= Red + Orange= Red + Red + Yellow= 2 + 2 + 3= 7
Yellow Orange= Yellow + Orange= Yellow + Red + Yellow= 3 + 2 + 3=8
Indigo= Blue + Purple= Blue + Blue + Red= 1 + 1 + 2= 4
Magenta= Red + Purple= Red + Blue + Red= 2 + 1 + 2= 5
Bluegreen= Blue + Green= Blue + Blue + Yellow= 1 + 1 + 3= 5
Yellow Green= Yellow + Green= Yellow + Blue + Yellow= 3 + 1 + 3= 7
White= Blue + Red + Yellow= 1 + 2 + 3= 6
Black= This one is the challenge. Black is not a colour as such, it's the absence of light. It absorbs all light making it appearing dark. So I'm not putting a number to this one, if I did it would be= 0
total of all colours= Blue + Red + Yellow + Green + Purple + Orange + Red Orange + Yellow Orange + Indigo + Magenta + Blue Green + Yellow Green + White + Black= 1 + 2 + 3 + 4 + 3 + 5 + 7 + 8 + 4 + 5 + 5 + 7 + 6 + 0= 60
Product of all colours= Blue * Red * Yellow * Green * Purple * Orange * Red Orange * Yellow Orange * Indigo * Magenta * Blue Green * Yellow Green * White * Black= 1 * 2 * 3 * 4 * 3 * 5 * 7 * 8 * 4 * 5 * 5 * 7 * 6 * 0= 0
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Post by Ark on Mar 5, 2006 20:00:51 GMT -5
PERFECT! GREAT JOB! Ok, Wirr now has one credit, next question, stolen from a random naruto fansite, all rules still apply.
Question: There are 3 scrolls, in which 2 of them contain explosive tags. Shikamaru asks you to pick the scroll that won't explode. You pick one scroll. Before you can open it, Shikamaru opens one of the remaining scrolls and poof, it explodes. He gives you the choice of either sticking with your original choice or switching to the remaining one.
Should you switch? Why?
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Post by Anime Monster on Mar 5, 2006 20:37:19 GMT -5
No, because it's usually your first guess that's right.
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Post by Ark on Mar 5, 2006 20:50:36 GMT -5
WRONG
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Post by Ark on Mar 6, 2006 9:32:35 GMT -5
It's not that difficult actually.
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me
Forum Newbie
Yeah Hikaru and Kaoru!
Posts: 48
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Post by me on Mar 6, 2006 15:06:10 GMT -5
switch.. i read the curious incident of the dog in the night time, the formula they give is complex but basically if you switch you have 2/3 chance of getting right.
let the scrolls be called x,y,z
let Cx be the event where x is the non explosive scroll
let Hx be the event that you chose scroll x. so the formula that you swich choices and not get blown up is
P(Hz^Cy) + P(Hy^Cz)
=P(Cy). P(Hy|Cy)+ P(Cz).P(Hy|Cz)
=(1/3.1)+(1/3.1) =2/3
I don't get the formula but the diagram is understandable... i just cant post it...
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